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Typo.

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Gael Guennebaud 2016-07-26 12:12:53 +02:00
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doc/InplaceDecomposition.dox
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@ -53,6 +53,7 @@ Then, one can use the \c lu object as usual, for instance to solve the Ax=b prob
</table>
Here, since the content of the original matrix \c A has been lost, we had to declared a new matrix \c A0 to verify the result.
Since the memory is shared between \c A and \c lu, modifying the matrix \c A will make \c lu invalid.
This can easily be verified by modifying the content of \c A and trying to solve the initial problem again: